5x^2-31=1=

Solution for 5x^2-31=1= equation:

5x^2-31=1=

We move all terms to the left:

5x^2-31-(1)=0

We add all the numbers together, and all the variables

5x^2-32=0

a = 5; b = 0; c = -32;
Δ = b2-4ac
Δ = 02-4·5·(-32)
Δ = 640
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{640}=\sqrt{64*10}=\sqrt{64}*\sqrt{10}=8\sqrt{10}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{10}}{2*5}=\frac{0-8\sqrt{10}}{10}
=-\frac{8\sqrt{10}}{10}
=-\frac{4\sqrt{10}}{5}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{10}}{2*5}=\frac{0+8\sqrt{10}}{10}
=\frac{8\sqrt{10}}{10}
=\frac{4\sqrt{10}}{5}
$